Re: [Boost-users] Boost::Multi_array and reducing dimensions

4 Jul 2008

      On Jun 30, 2008, at 9:46 AM, Joey Mukherjee wrote:
...
On Jun 27, 2008, at 11:16 AM, Ronald Garcia wrote:
...
On Jun 26, 2008, at 2:43 PM, Joey Mukherjee wrote:
...
Suppose this type of setup was within a function, is it possible  
to make OneDView the return value of this function?  In other  
words, I would like to:
array_type::const_array_view <1>::type OneDView;
OneDView = multi_array[myindices];
return OneDView;
Off-hand, I see no reason why you couldn't do this.  So long as the  
multi_array is still in existence, you can build and keep a view of  
it.  How are you calling your function?  I'm afraid I can't tell  
what the problem might be since I can't see how it's really used.
What would be the return value of the function?  In other words,  
what would the function prototype be?  As in the code above, I am  
not allowed to assign to a OneDView.  How can I write it so that I  
am able to?
Rather than assign to a OneDView, you can construct a OneDView as the  
result of a function call:

typedef boost::multi_array array_t;

array_t::const_array_view<1>::type
get_view (array_t& A) {
   return A[boost::indices[0][array_t::index_range()]];
}

int main() {

   array_t A(boost::extents[2][2]);

   array_t::const_array_view<1>::type
     V = get_view(A);
}

Perhaps I don't understand what you're trying to do.
...
The way I have my function, I am calling it like so:
double GetRealData (const SensorInfo &si, const std::vector <double>  
&vals, const unsigned int whichPosition)
The vals is a n-dimensional array of doubles and the si variable has  
the desired slice and the sizes of my array.  Rather than return a  
double, I would like to return a one-dimensional const_array_view.
If you don't know at compile-time how many dimensions your array is,  
then I think that you will need to copy the view into a one- 
dimensional multi_array.
...
Thanks for your help!
Joey
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