Re: [Boost-users] a problem about boost::regex

28 Apr 2008


      Hi, John
I have a string splited by "\0"  ( it means {'\\','0'}, the bellow is the
same ),
for example: "\0xxxx\0yyyy\0zzzz\0".
And there is some special situation like
"\0xxx\\0\0yyy\\\0zzz\0" , you can think it is similarly to c style string,
the two '\\' means a single '\'
and the '\\0' is not a spliter.
i want to split them in to
0) xxx\\0
1) yyy\\
c) zzz

how can i do it in boost::regex?
thx,all
...
Message: 7
Date: Sat, 26 Apr 2008 12:52:43 +0100
From: "John Maddock" 
Subject: Re: [Boost-users] a problem about boost::regex
To: 
Message-ID: <002d01c8a794$0d593e50$eeea0352@fuji>
Content-Type: text/plain; format=flowed; charset="UTF-8";
       reply-type=original
Guo Xu wrote:
...
...
a regex expression:
(?<=[^\\](?:\\\\)*)\\0
can work well in c#, but error in boost::regex
why?
Variable length lookbehind isn't supported in Boost.Regex (or in Perl for
that matter).
Regards, John.