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4 Mar
2009
4 Mar
'09
11:10 p.m.
From: "Peter Dimov"
Subject: Re: [Boost-users] [enable_shared_from_this] My derivation ofenable_shared_from_this wants to be templated
template<class X> class Y: public enable_shared_from_this< Y<X> > { public:
shared_ptr< Y<X> > f() { return shared_from_this();
In a template, you need
return this->shared_from_this();
to inform the compiler that shared_from_this will come from a base class.
}
perfect ... thank you.