On 4/3/2012 10:50 PM, paul Fultz wrote:
Yea, sorry about that. It seems it was still calling my own invoke and there was a mistake in that. If you call invoke like this:
std::cout << invoke(mutable_func(), forward_as_tuple(i, 1)) << std::endl;
There are two errors:
invoke.hpp:209:24: error: non-const lvalue reference to type 'int' cannot bind to a temporary of type 'int' return f( BOOST_PP_ENUM(N,M,~) ); ^~~~~~~~~~~~~~~~~~~~~~~~~
Which I assume is because invoke takes the sequence as a const-reference because it is a temporary. But then why does the other example work(its also a temporary)?
The int& held in the tuple will always be mutable regardless if the holder tuple is const, that is why it works. I don't know what else you are doing with forward_as_tuple. Regards, -- Joel de Guzman http://www.boostpro.com http://boost-spirit.com