Re: [Boost-users] [type_traits] deduce argument type of member function with function_traits

On Saturday, September 3, 2011 1:41:41 AM UTC-7, niXman wrote:

May be: http://www.boost.org/doc/libs/1_47_0/libs/function_types/doc/html/boost_func...

?

good to know! but I still get an error, on this new version. error: no matching function for call to ‘test(<unresolved overloaded function type>)’ /tmp/tt.cpp:25:6: note: candidate is: void test(F) [with F = char (csquare_impl::*)(char)const] but "run" is not overloaded !, and I don't know how to cast to resolve the overload. #include <typeinfo> #include <iostream> #include #include #include #include #include #include using namespace std; double dsquare(double l){ return l*l; } int isquare(int l){ return l*l; } struct csquare_impl{ char run(char c) const{return 'c';} }; csquare_impl csquare; template<class F> void test(F f){ // works // typename boost::function_traits::arg1_type test_var; // works too, more elegant(?) typename boost::mpl::at_c::type test_var; cout << typeid(test_var).name() << endl; } int main(){ test(dsquare); // ok, prints "d"(double) test(isquare); // ok, prints "i"(int) test(csquare.csquare_impl::run); // not ok, want to print "c"(char) return 0; } BTW, this type traits is a mess, everything it is all over the place, Boost.FunctionTypes, Boost.TypeTraits.FunctionTraits, Boost.Functional.

2011/9/3 alfC

...

Is function_traits the right way to extract the argument type of a member function?

In the following example I want to make the last line work. This will be part of larger question, on how to deduce the argument type of operator() for function objects in which operator() is not overloaded.

#include <typeinfo> #include <iostream> #include #include

using namespace std;

double dsquare(double l){ return l*l; } int isquare(int l){ return l*l; }

struct csquare_impl{ int do(char c) const{ return 'c'; } }; csquare_impl csquare;

template<class F> void test(F f){ typename boost::function_traits::arg1_type test_var; cout << typeid(test_var).name() << endl; }

int main(){ test(dsquare); // ok, prints "d"(double) test(isquare); // ok, prints "i"(int) test(csquare_impl::do); // not ok, want to print "c"(char) return 0; }

Thanks, Alfredo

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