Re: [Boost-users] Lambda expressions

--- David Abrahams wrote:

Lucio Flores writes:

...

I posted this question a few months ago, but I got pulled away to deal with more pressing work issues. So here it goes again:

I'm trying to use lambda expressions to implement 'twice'. So I came up with

typedef mpl::apply<_1, mpl::apply<_1, _2> > lambda_type;

typedef lambda_type, int> result_type;

Surely that doesn't compile(?) lambda_type is a type; you can't follow it with a template argument list.

You're right! .... But it did compile.... So what's the correct usage? Would it be: typedef mpl::apply< lambda_type, boost::add_pointer<_1>, int>::type result_type; ??? ------------------------------------------- Manson: My philosophy is: Don't think. I don't believe in the mind that you think with and scheme with. I don't believe in words. Reporter: If you don't believe in words, why do you use so many of them? Manson: Words are symbols. All I'm doing is jumbling the symbols in your brain. Everything is symbolic. Symbols are just connections in your brain. Even your body is a symbol. __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com