hi,
i have a c++ function that returns a reference to a c++ object. i want
to expose this function to Python making it return the Python version
of the object. i'm using Boost.Python.
i understood that i have to use to_python_converter but the body of the
A_to_Python::convert function is mystery for me. Boost documentation's
example solves the problem in a manner i'm not able to apply to my case.
my A object is complex and i'd like to somewhat (re)use the class_ object.
---------------- CUT HERE ----------------
#include
using namespace boost::python;
struct A
{
void f() {}
};
A a;
struct A_to_Python
{
static PyObject* convert(const A& a)
{
// documentation says:
// return PyObject_New(noddy_NoddyObject, &noddy_NoddyType);
}
};
A& get_A() { return a; }
BOOST_PYTHON_MODULE(hello)
{
class_<A>("A")
.def("f", &A::f)
;
to_python_converter();
def("get_A", get_A, return_value_policy());
}
---------------- CUT HERE ----------------
please, somebody enlighten me.
many thanks
domenico
-----[ Domenico Andreoli, aka cavok
--[ http://filibusta.crema.unimi.it/~cavok/gpgkey.asc
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