Re: [Boost-Users] Most efficient way to convert a run of Perl substitutions til boost::regex?

static const boost::regex re1("jou"); static const boost::regex re1("jau"); static const boost::regex re1("nch"); static const std::string fs1("sju"); static const std::string fs2("sjo"); static const std::string fs3("ngk");

std::string res = regex_merge( regex_merge( regex_merge(input_string, re1, fs1) , re2, fs2) , re3, fs3);

Have you thought about combining these into one big regex: static const boost::regex e("(jou)|(jau)|(nch)"); static const std::string format_string("(?1sju)(?2sjo)(?3ngk)"); // conditional format string regex_merge(input_string, e, format_string); // search and replace everything at once John.