Thank you for the reply
I am still a bit lost
for example, the doc says
subtractable<T>
produces T operator-(const T&, const T&)
It requires:
"
T temp(t); temp -= t1.
"
so does this mean
T& operator -= (const T& ) ?
---
this is a separate question:
I have implemented the <addable> tempalte with +=
(as in the point example, but made it return a reference)
then I do
cmoney_t a("300");
cmoney_t b("100");
a+=b;
and I see in the debugger that
the *this in the operator += points to 100, not to 300
I am sure I am doing something wrong, but I thought
in the += operator, *this would mean the value of "a" variable
not "b".
Is at least my understanding correct, that *this should be pointing to
300,
and not 100?
thank you again,
Vlad
On Mon, 23 Mar 2009 10:41 -0500, "Alan M. Carroll"
At 09:55 AM 3/23/2009, V S P wrote:
I am using this example http://www.boost.org/doc/libs/1_38_0/libs/utility/operators.htm#example
but cannot understand why object is returned from those operators and not an object reference
That certainly is odd. It means that the following code will not work as expected:
point x(0,0), y(1,0), z(0,1); (x += y) += z; // x is (1,0), not (1,1).
second, I do not quite understand, what exactly is a set of 'automatically generated' operators and would I figure that out.
It is documented in the comments of the example you cite, and listed in the table[1] just below.
[1] http://www.boost.org/doc/libs/1_38_0/libs/utility/operators.htm#smpl_oprs
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