Re: [Boost-users] variant cast operators?

On Mon, 17 Mar 2008 20:05:58 -0000, Daniel Oberhoff wrote:

Hi,

I am playing with boost::variant to introduce a more elegant property system into my current project. I was wondering why there are no cast operatorst defined for the variant types, to avoid having to type get<>:

boost::variant v; string s = v;

is there a basic reason why this is not possible?

I guess it's because it's pretty dangerous to do implicit casts that may fail. Regards Jiri Palecek