25 Aug
2008
25 Aug
'08
4:06 p.m.
On Mon, Aug 25, 2008 at 09:13:49AM +0200, Carsten Høyer wrote:
That wouldn?t be enough would it? Then i only have the connection between the two
The easiest way to do it is to introduce a new node for every port, but then you will loose the information about grouping of ports into your "original" nodes. So you'd need an extra structure / subgraph that accomplishes the latter. Maybe an extra property on the ports which signifies to which "node" they belong.