Marco Meoni - Sbaush wrote:
> Yes.
> I did an example like this
to learn how to serialize in the
> "classical" way.
>
>
> My problem is that i can't define a serialize method inside
>
Container, but i would serialize it anyway. How can i serialize the
>
Example strut entirely?
>
>
> Do you understand my
problem?
>
>
> On Fri, Apr 30, 2010 at 3:49 AM, Robert Ramey
<
ramey@rrsd.com> wrote:
>
> Marco Meoni - Sbaush
wrote:
>> Can someone help me?
>> Robert, where can I find
what you're talking about?
>
> I don't know what you're trying to
do so I'll take a guess.
>
> Does this look like what you want to
do?
>
> struct Container {
> int
m_container_member;
> ... // more
members
> template<class
Archive>
> void serialize(Archive & ar,
const unsigned int
version){
> ar &
m_container_member;
> ...
// more members
> }
> };
>
>
struct Example {
> friend class
boost::serialization::access; // not really
> necessary as all "struct"
members are public
> template<class
Archive>
> void serialize(Archive & ar,
const unsigned int
version){
> ar &
m_container;
> }
> };
>
> int
main(int argc, char * argv[]){
> const Container c
= ...
> std::fostream
os("filename");
> boost::serialization::archive
ar(os);
> ar & c;
> }
>
>
Does that help any?
>
> Robert Ramey
>
>
>
_______________________________________________
> Boost-users mailing
list
>
Boost-users@lists.boost.org>
http://lists.boost.org/mailman/listinfo.cgi/boost-users