Re: [Boost-users] [bind] how to get a funtor of a function since the function's template argument is a functor

hongleij@126.com wrote:

#include #include

#include <iostream>

class BufferMoniter { public: void maitain() { std::cout <<" BufferMoniter" << std::endl; } }; class LocalPeer { public: template <class T> void caller(unsigned int interval,T t) { //do something t(); } void fork() { BufferMoniter *pBuffer=new BufferMoniter( ); boost::thread thrd(caller(500,boost::bind(&BufferMoniter::maitain,pBuffer)) ; // that i really want.a fuctor of caller(500,boost::bind(&BufferMoniter::maitain,pBuffer).

thre.join(); }

The easiest way is to use boost::function to hide the type of T. This will also take care of one additional problem with interpreting the inner bind as a nested subexpression. void caller(unsigned int interval, boost::function const & t) { //do something t(); } void fork() { shared_ptr<BufferMoniter> pBuffer( new BufferMoniter() ); // take care of leak boost::function f = boost::bind(&BufferMoniter::maitain,pBuffer); boost::thread thrd( boost::bind( caller, 500, f ) ); thrd.join(); }