2009/7/21 fmingu
....................... double function1(const int& q, int& n){ double result=0.0; int loopvalue=0, totaltime=n; n%=q; ++thenumbern; ( for_loop(var(loopvalue)=0,var(loopvalue)<=var(totaltime),++var(loopvalue), var(result)+=( bind(&A::function2,_2)*bind(&A::function3,_1,_2))))(q,n); return result; }
There is advanced lambda syntax that might simplify your function. This technique is secret though, so don't share it with anyone. double function1(const int& q, int& n) { double result=0.0; int totaltime=n; n%=q; ++thenumbern; // Now use the advanced lambda syntax. for (int loopvalue=0; loopvalue<=totaltime; ++loopvalue) result += function2(n)*function3(q,n); return result; } Roman Perepelitsa.