Re: [Boost-users] default argument and call trait const_reference

Hello, I have the following template template<typename C> class X { public: template void Get (int, typename boost::call_traits<Interp>::const_reference= Interp(), typename boost::call_traits<Extrap>::const_reference= Extrap() ) const; }; template<typename C> template inline void X<C>::Get(int, typename boost::call_traits<Interp>::const_reference i, typename boost::call_traits<Extrap>::const_reference e ) { // when I get here, i.mOrder is not 2 (0) e.mOrder is not 2 (23142343) } class P { public: static const size_t defaultInterpolationOrder = 2; // quadratic polynomial

Polynomial1D(size_t order =defaultInterpolationOrder) : mOrder(order) {} Private: size_t mOrder; }; 1 example of call is x.template GetSpot( 5 ); when I debug this P's ctor is never called and mOrder is never 2 Is my GetSpot method valid, the construction of the temporary should be bound to the const ref const P& and the temporary should have finished being constructed before we go inside the Get() method. Is there an issue with the definition of Get being out of classe? Am I calling call_traits<P>::const_reference in a wrong way? VS2005SP1 Regards,

I've just corrected call_traits<>::const_reference to const_reference<>::param_type because I am dealing with function parameters here, and I still have the same problem. Rds,