I came across this problem in the real project where I don't control the class that corresponds to class Y of the example, so I can't change the signature of the member function. I could write a wrapper function that takes Y*, but after some point the code with a simple 'for' loop becomes cleaner and more readable than the one using lambda. If this problem is not a bug, but an inherent limitation of the lambda library or its current implementation, it would be nice if it is mentioned in the documentation. Thanks, Eugene Vishnevetsky Roman Krylov wrote: Perhaps the only solution here is to use Y* instead of Y& with corresponding modifications; this way there is no need for var() or smth similar. Why not? Vishnevetsky, Eugene (IT) wrote: >Is it possible to use boost::ref() or boost::lambda::var() of an >abstract class as a parameter to boost::lambda::bind()? >It seems that compiler attempts to instantiate an object of that >abstract class. >Example: > >----------------- >using namespace boost; >using namespace boost::lambda; >class Y >{ >public: > virtual void foo() = 0; > void foo2 (){ } >}; >class Z : public Y >{ >public: > void foo(){} >}; > >class TT >{ >public: > void test( Y& y ) { y.foo2(); } >}; > >int main() >{ > std::vector<TT> xt; > Z z; > Y &y = z; > std::for_each (xt.begin(), xt.end(), bind(&TT::test,_1, >ref(y))); > return 0; >} >---------------------- > >And Error message from g++ (GCC) 3.2.3: > >--------------------------------- >/boost/tuple/detail/tuple_basic.hpp: In instantiation of >`boost::tuples::cons<Y, boost::tuples::null_type>': >/boost/tuple/detail/tuple_basic.hpp:326: instantiated from >`boost::tuples::cons<boost::tuples::null_type, boost::tuples::cons<Y, >boost::tuples::null_type> >' >/boost/tuple/detail/tuple_basic.hpp:326: instantiated from >`boost::tuples::cons<void (TT::*const)(Y&), >boost::tuples::cons<boost::tuples::null_type, boost::tuples::cons<Y, >boost::tuples::null_type> > >' >/boost/lambda/detail/lambda_functor_base.hpp:151: instantiated from >`boost::lambda::detail::has_null_type<boost::tuples::cons<void >(TT::*const)(Y&), boost::tuples::cons<boost::tuples::null_type, >boost::tuples::cons<Y, boost::tuples::null_type> > > >' >/boost/lambda/detail/lambda_functor_base.hpp:229: instantiated from
`boost::lambda::detail::deduce_non_ref_argument_types<boost::tuples::tu
p le<void (TT::*const)(Y&), const boost::lambda::lambda_functor<boost::lambda::placeholder<1> >, Y&, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type>, boost::tuples::null_type>' /boost/lambda/detail/lambda_functor_base.hpp:412: instantiated from `boost::lambda::lambda_functor_base<boost::lambda::action<3, boost::lambda::function_action<3, boost::lambda::detail::unspecified>
, boost::tuples::tuple<void (TT::*const)(Y&), const boost::lambda::lambda_functor<boost::lambda::placeholder<1> >, Y&, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type> >::sig<boost::tuples::null_type>' /boost/lambda/detail/lambda_functors.hpp:135: instantiated from
:lambda::action<3, boost::lambda::function_action<3, boost::lambda::detail::unspecified> >, boost::tuples::tuple<void (TT::*const)(Y&), const boost::lambda::lambda_functor<boost::lambda::placeholder<1> >, Y&, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type> > >' lamtest.cpp:35: instantiated from here /boost/tuple/detail/tuple_basic.hpp:320: cannot declare field `boost::tuples::cons<Y, boost::tuples::null_type>::head' to be of type `Y' /boost/tuple/detail/tuple_basic.hpp:320: because the following virtual functions are abstract: lamtest.cpp:12: virtual void Y::foo() ----------------------------------------
Thanks,
Eugene Vishnevetsky --------------------------------------------------------
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