Eric Niebler wrote:
Ovanes Markarian wrote:
Hello Eric,
sorry for bothering. I use xpressive in the following context:
<snip>
I can't get your code to compile. Please send a minimal and complete source file that demonstrates the problem.
After fiddling with your code a bit, I got it to compile, but I'm not seeing any assertions, exceptions or crashes. What version are you using? Below is the full source. I had to comment out the line to toks.size() -- iterator_range::size() requires random access iterators, and regex_token_iterator is not random access. I can't imagine how this compiles for you. Also, your example is highly suspect at this line: std::string includes = *++toks.begin(); iterator_range::begin() returns an iterator *by value*. The ++ is mutating the copy, not the iterator stored in the range. Did you mean to do that? #include <string> #include <iostream> #include <boost/tr1/functional.hpp> #include <boost/range/iterator_range.hpp> #include <boost/xpressive/xpressive.hpp> namespace x = boost::xpressive; typedef x::sregex regex_type; const regex_type non_semicolon = ~x::as_xpr(';'); const regex_type sem_separated = *non_semicolon; typedef boost::iterator_range<x::sregex_token_iterator> regex_tokens; typedef ::std::vector<regex_tokens> regex_transformed_collection; inline regex_tokens apply_regex(regex_type const& re, std::string const& item) { typedef x::sregex_token_iterator sre_iter; return boost::make_iterator_range(sre_iter(item.begin(), item.end(), re), sre_iter()); } // usage: int main() { std::vector<std::string> v; //vector is filled with strings of type: some_part;some_other_part typedef regex_transformed_collection::const_iterator re_citer; regex_transformed_collection sep_strings; ::std::transform ( v.begin(), v.end(), ::std::back_inserter(sep_strings) , ::std::tr1::bind(&apply_regex, sem_separated, std::tr1::placeholders::_1) ); //v is in the same scope and valid for(re_citer curr=sep_strings.begin(), end=sep_strings.end(); curr!=end; ++curr) { regex_tokens const& toks = *curr; std::string source = toks.front (); //this line is fine and returns me the first part of a string... // all subsequent line will raise an assertion std::string includes = *++toks.begin(); //size_t sz = toks.size(); } return 0; } -- Eric Niebler Boost Consulting www.boost-consulting.com