On 16 May 2008, at 18:43, Noah Roberts wrote:
Kevin Martin wrote:
And to make matters worse, people might be tempted to do this!
func1(func2().get());
Having fixed that, your call looks like this:
func1(*func2());
My understanding of how this works was wrong. I thought the object returned by func2 would go out of scope before the call to func1, meaning the pointer/reference passed to func1 would be hanging. It seems I am wrong though, at least with g++ and icc, so I guess I need to go back to C++ 101. func1() may be a member function of an object which needs to keep the argument somewhere, that is why I prefer to pass a pointer. Passing a reference gives the implication (at least to me) that the object is not going to keep any link with the argument after the call returns. Passing a pointer makes me think - hey, what is this object doing with this thing? Thanks, Kevin Martin