[Boost-users] Re: lexical_cast<string> of type char

Miro Jurisic writes:

In article , "DY, JERRY U (SBCSI)" wrote:

...

string s2 = lexical_cast<string>((int)c) // s2 = "65"

I would have written int(c) instead of (int)c because compilers perform more useful checking on the constructor than they do on the cast, but that's all.

The two forms are equivalent. -- Dave Abrahams Boost Consulting http://www.boost-consulting.com