None of the examples, for list_of, show the use of the default list_of
constructor. When I tried to use list_of() for a vector I expected a
blank vector without any elements. What I found was a vector that had
one element of the vector type. This element had a default value. Is
this the correct behavior?
t_ucvector temp( list_of() ); //The temp vector has one element of type
unsigned char with a default value of zero.
There is a structure with a couple of constant std::vectors that are
being initializing in the constructor's preamble. I've included the
structure with the working version of the code. I've included the
desired creation of the std::vector, but because of list_of() is not
working.
Thank you for your help.
Ryan
struct SplitterFixture
{
public:
SplitterFixture(void)
: header(list_of(2)(2))
, messageA(list_of('a').repeat(2,'a'))
, input(t_boostVector(new t_ucvector(list_of(2)(2).range(messageA))))
//Desired implementation.
//: header(list_of().repeat(2,'2'))
//, messageA(list_of().repeat(3,'a'))
//, input(t_boostVector(new
t_ucvector(list_of().range(header).range(messageA))))
{}
public:
typedef std::vector<unsigned char> t_ucvector;
typedef boost::shared_ptr