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----- Original Message -----
From: "Steven Watanabe"
AMDG
Terry Golubiewski wrote:
Warning: untested code
typedef quanttyus::foot_base_unit::unit_type Length; Length x(2.0 * m);
Ok. That makes Length represent "feet" But I want Length to remain represented as an si::length, but input "ft" into it and convert to "ft" to print.
// static const si::length ft = ???; typedef quantitysi::length Length; Length x = 3.0 * ft; cout << "x=" << convert_to_ft(x) << endl;
typedef quantityus::foot_base_unit::unit_type convert_to_ft;
Got it! Now the other part... typedef quantitysi::length Length; Length x = 3.0 * ft; If x is an SI unit, how can I convert from "ft"? I'm missing something, but I'm not sure what. terry