Re: [Boost-users] A simple question involving boost.function and boost.lambda

I have tried: function0<void> funcs = (func1, func2); but this seems to execute only one of the two functions when it is called.

Here no lambda expression is involved. It is equivalent to "funcs = func2;".

I have also tried: function0<void> funcs = (_1(), _2())(func1, func2);

Mhm, don't know whether this should work. However, the following does: function0<void> funcs = ( bind<void>(func1), bind<void>(func2) ); You just delay the call to the function objects, as you would do with a function. Wolfgang Meyer