Re: [Boost-users] variant<> number of template arguments

Thank you, Trying to define the variant, I have: typedef boost::mpl::vector<> variant_template_arguments; typedef boost::mpl::vector interpolator_types; typedef boost::mpl::vector<simpson> integrator_types; I have a curve template template curve; I want to generate the list of all curves by iterating the template args in the vector<> and inserting these curves in variant_template_arguments to finally typedef make_variant_over< variant_template_arguments >::type my_wanted_variant; How should I do the iteration/insertion in variant_template_arguments? Rds, -----Original Message----- From: boost-users-bounces@lists.boost.org [mailto:boost-users-bounces@lists.boost.org] On Behalf Of Steven Watanabe Sent: 29 May 2008 23:53 To: boost-users@lists.boost.org Subject: Re: [Boost-users] variant<> number of template arguments AMDG Hicham Mouline wrote:

Question1: is the maximum number of variant<> arguments extendable?

The easiest way is to use make_variant_over which takes an MPL sequence.

Question2: Below, some of the variants I have are full template specs.

Is there a way to write the variant<> typedef with templates instead and have

the operator() of the static visitor a template member.

I'm not sure what you want. If the members of the variant have a common interface, (For example if they all have a nested integer constant called value) Then you can make the static visitor operator() a template and use this common interface. In Christ, Steven Watanabe