Re: object_pool use ordered_malloc ordered_free. why?

Destroying single objects that were created from an object_pool uses ordered_free, as you discovered. An object_pool will keep its free list ordered, so that it can run through the "list of allocated objects" in O(N) time instead of O(N**2) time in ~object_pool. It's a performance tradeoff with object_pool::destroy; object_pool was designed more for a "allocate a bunch of objects and then destroy all of them" type of scenario.

-Steve

thanks. if i only construct one and destroy exactly. is the order_xxx not need now? and (maybe?) i don't care the performance in ~object_pool. i use pool to avoid mem-piece. so i implement a simple ObjectPool (see below). i think random construct and destroy is fast now. is right? #include template <typename T> class ObjectPool { public: ObjectPool() : rawpool(sizeof(T)) {} T * construct() { T * ret = static_cast(rawpool.malloc()); if (ret == 0) return ret; try { new (ret) T(); } catch (...) { rawpool.free(ret); throw; } return ret; } void destroy(T *p) { p->~T(); rawpool.free(p); } private: boost::pool<> rawpool; };