Hello, all:
I met a strange compile error, this code will reproduce the problem::
#include
#include
#include <iostream>
namespace foo {
struct bar {};
}
std::ostream& operator << (std::ostream& out, foo::bar) {
return out << "BAR";
}
int main() {
boost::lexical_caststd::string(foo::bar());
}
However, if I just remove that unused include boost.variant, it works::
#include
//#include
#include <iostream>
namespace foo {
struct bar {};
}
std::ostream& operator << (std::ostream& out, foo::bar) {
return out << "BAR";
}
int main() {
boost::lexical_caststd::string(foo::bar());
}
Another solution is put that "operator<<" in namespace foo::
#include
#include
#include <iostream>
namespace foo {
struct bar {};
std::ostream& operator << (std::ostream& out, foo::bar) {
return out << "BAR";
}
} // namespace foo
int main() {
boost::lexical_caststd::string(foo::bar());
}
Anyway, what is boost.variant's business here?
Won't that fail to compile, or am I missing something?
BTW, I'm using boost 1.48.0 and gcc 4.6.2 in Linux 3.2.2.
Regards,
Tianjiao
