2009/1/25 Michał Nowotka <mmmnow@gmail.com>:
Right, there is a mistake.
So the problem is:
Suppose i defined: typedef std::vector<std::pair<const SomeClass*,double>* > MyType;
So if I want to keep DRY i should write:
lambda::_1 ->*&MyType::value_type::second > lambda::_2 ->*&MyType::value_type::second);
I also tried: bind(&MyType::value_type::second, lambda::_1) > bind(&MyType::value_type::second, lambda::_2)
but none of this expression works for me.
Well, it's hardly surprising, as the value_type of the vector is a pointer, so won't have a member called 'second'. Let's refactor the DRY-ness a little: typedef std::pair<const MyClass*,double> ElemType; typedef std::vector<ElemType *> MyType; MyType v; Then you can use this: std::sort(v.begin(), v.end(), bind(&ElemType::second, _1) > bind(&ElemType::second, _2)); ? Stuart Dootson