Re: [Boost-users] using lambda's pointer to member functionandboost::function

function f = (&_1->*&aux::a)();

This doesn't work because you are evaluating the functor without arguments, whereas it requires one.

function f = bind( &aux::a, _1 );

This would work, but I in my project I have to call operator->* because in my case aux is a class that models a pointer, but doesn't have a dereference operator, just operator->* and operator->, those are the only ways to access the containing pointer. Well, there's also a ptr member function that returns it, but I'm trying to achieve the most natural way to access the containing pointer members. By using aux's ptr member, I have to use bind functions, which is a little unnatural.

or

function f = &aux::a;

That doesn't make it either because f(a) just would return a delayed call to &aux::a, not its actual result. By trying to correct your first example, I've come with: function f = (&protect(_1)->*&aux::a)(); The rationale is that the first evaluation without parameter would return a functor that expects an aux object, and would return aux::a return value (int), but this also fails compiling because class other_action::apply fails to conclude that &protect(_1) is actually a pointer, and so it calls member_pointer_action_helper::apply, which is the wrong choice. IMO the right choice would be member_pointer_action_helper which evaluates the pointer to member function. Thanks for your help, Rodolfo Lima.