Can I declare a pure virtual member function which accepts as input a boost shared pointer to an object of a base class, such that - clients of the function can pass in as input a boost shared pointer to an object of a derived class - concrete implementations of the function can redirect the pointer to a new object of an (even more) derived class ? Consider the following class hierarchy in the problem domain: class Serializable {}; class Foo : public Serializable {}; class Bar : public Foo {}; Here is the pure virtual member function I would like to declare: class Serializer { public: virtual void serializeObject(boost::shared_ptr < Serializable > &) = 0; } And the relevant subset of one of its concrete implementations: class XmlReader : public Serializer { virtual void serializeObject(boost::shared_ptr < Serializable > &p) { p = boost::shared_ptr < Serializable > (new Bar()); } } The client would call the function like this: boost::shared_ptr < Foo > foo; Serializer *s = new XmlReader(); s->serializeObject(foo); The above code doesn't compile, the error message from VC6 is main.cpp(72) : error C2664: 'serializeObject' : cannot convert parameter 1 from 'class boost::shared_ptr<class Foo>' to 'class boost::shared_ptr<class Serializable> &' The best solution I have found so far is to declare the function like this: class XmlReader : public Serializer { virtual boost::shared_ptr < Serializable > serializeObject() { boost::shared_ptr < Serializable > ret = boost::shared_ptr < Serializable > (new Bar()); return ret; } } And call it like this: foo = boost::dynamic_pointer_cast< Foo >(s->serializeObject()); But that's not ideal for my purposes, I would prefer to have a function which modifies its inputs and returns void. I can't implement the function as a template because I need it to be virtual. Any assistance gratefully received. Regards, Eric