lambda library: how to use io manipulators?

16 May 2003

      The following compiles:

     (cout << _1 << "\n")(x);

but this doesn't:

     (cout << _1 << endl)(x);

(gcc 3.2.2)

I can't figure out how to use an io manipulator within a lambda function.

Firstly, how do I do it?  (e.g. suppose I want to use flush, for which 
there is no workaround like using "\n").

Secondly, a suggestion: it would be nice if support was built in for the 
io manipulators.

     - Chuck

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