Re: [Boost-users] return type of boost::bind

Duane Murphy wrote:

The return type of boost::bind is fairly indeterminate. In order to call a bound function at a later time, look at boost::function. It does a nice job of holding on to a function that uses boost::bind.

I looked at "Using bind with Boost.Function" in the boost::function docs. Mimicing that, for my example, I tried: boost::function bound_func = boost::bind(f, _1, 1.234); int i = 99; cout << bound_func(i) << endl; but it throws a bad_function_call exception when bound_func(i) is invoked. How do I use boost::function for this situation? Thanks. Cheenu I wrote:

...

I wish to store the return value of boost::bind in an intermediate object to invoke it at a later time. I only ever see examples which combine the call to boost:bind with the immediate invocation on the returned object such as:

#include using namespace boost; #include <iostream> using namespace std;

double f(int i, double d) { cout << "int = " << i << endl; return d; }

main() { int i = 99; cout << bind(f, _1, 1.234)(i) << endl; }

Instead I'd like to postpone the call to the returned object. What's the type of obj?

main() { int i = 99; WHAT_IS_MY_TYPE obj = bind(f, _1, 1.234); ... cout << obj(i) << endl; }