On Wednesday 13 February 2008 19:05:16 Kobi Cohen-Arazi wrote:
I'm taking a wild guess here not knowing what you're running this on (and I really haven't looked into your code much), but try:
t.template get<0>(); t.template get<1>();
Was that it?
Stjepan
It compiles w/o error. Thanks!
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Is it possible for the boost/template gurus to explain why it is needed here?
Any help would be appreciated,
I'm no template guru but (the same as typename), template may be used in such contexts to tell the compiler that the following _dependent_ name (ie "get") is to be treated as a template and not (as it assumes by default) as say a data member. Because if it was a data member then get<0 actually means operator<(get, 0) and not part of the syntax to instantiate the template "get". So then you must tell the compiler "get" is a template. Notice I underlined "dependent", it means this is needed in contexts where the name depends on a template parameter, so if "t" is of a template parameter type (or dependent on such a parameter) then the compiler cannot know in "t.name", if "name" is suposed to be a member, a nested non-template type or a template (class or function, doesn't matter). It will require additional specification from you (otherwise assumes to be a member, except some contexts in which it assumes to be a non-template type), in our case it requires that we tell it that "get" is a template for all "t"s possible in that context. I hope I got it right... -- Mihai RUSU Email: dizzy@roedu.net "Linux is obsolete" -- AST