Re: [Boost-users] [result_of]

26 Oct 2009

      Hi All,

I rephrase here a question to a previous post:

If G derives privately from F,
and F::result_type is defined,
but I provide, say, G::result<F1(T)>,

boost::result_of<G(T)>::type attempts to access the private 
F::result_type, instead of G::result<G(T)>::type.

I guess, if I really want to keep F a private base, I could wrap it in a 
class, W<F>, that does not expose result_type, yet I'm hoping someone 
might have a better idea.

Thanks.