Re: [Boost-users] [serialization] removing excess XML tags

Paul, You can turn off the wrapping boost_serialization tag by giving your archive the boost::archive::no_header switch. There's a boost::archive::no_tracking switch, but it doesn't seem to turn off the 'class_id' and 'tracking_level' stuff. John #include <fstream> #include <iostream> #include class MyClass { private: friend class boost::serialization::access; template<class Archive> void serialize(Archive &ar, const unsigned int version){}; public: MyClass(){}; friend std::ostream & operator<<(std::ostream &os, const MyClass &gp); virtual ~MyClass(){}; }; int main( int argc, char** argv[] ) { MyClass mc; // std::ofstream ofs("MyFile.xml"); boost::archive::xml_oarchive oa(std::cout,boost::archive::no_header); oa << boost::serialization::make_nvp( "MYTAG", mc ); return 0; } Paul Heil wrote:

I'd like to use the boost::serialization library to generate XML that must be read by a third party application. Unfortunately, this application does not like the extra stuff that the serialization library generates.

The code below generates XML that looks like this: <?xml version="1.0" encoding="UTF-8" standalone="yes" ?> <!DOCTYPE boost_serialization> <MYTAG class_id="0" tracking_level="0" version="0"></MYTAG>

What I need is XML that looks more like this: <?xml version="1.0" encoding="UTF-8" standalone="yes" ?> <MYTAG></MYTAG>

What can I do to eliminate the extra stuff?

Thanks, PaulH

class MyClass { private: friend class boost::serialization::access;

template<class Archive> void serialize(Archive &ar, const unsigned int version){};

public: MyClass(){}; friend std::ostream & operator<<(std::ostream &os, const MyClass &gp); virtual ~MyClass(){}; };

int main( int argc, _TCHAR* argv[] ) { MyClass mc;

std::ofstream ofs("MyFile.xml"); boost::archive::xml_oarchive oa(ofs); oa << boost::serialization::make_nvp( "MYTAG", mc );

return 0; } ------------------------------------------------------------------------

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