A t.join() before the return in main will wait for the other thread to
finish executing before finishing the program.
On Wednesday, December 7, 2011, Igor R
Thanks. The first extra argument solved the compilation issue, but I now get unexpected output (adding the suggested extra arguments does not help this). In particular, it seems that the second thread is not starting up, as I only get output from the main thread. The book says I should get a random interleaving of the lines outputted by each thread. My code:
void fxn1(){ for (int i=0; i<10; ++i){ cout << i << ") Do something in parallel with main method." << endl; boost::this_thread::yield(); }}
int main(){ boost::thread t(&fxn1); for (int i=0;i<10; i++){ cout << i << ". Do something in main method." << endl; } return 0; }
The second thread doens't have a chance to run. Try increasing the upper bound of the loops to one million or so. _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users
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