5 Aug
2008
5 Aug
'08
2:45 p.m.
Thank you. I understand that.
ps: It's my mis-express that the implicit conversion from T* to
shared_ptr<T>.
I mean that Boost.Python constructs a shared_ptr<T> by it's construction
method with a raw pointer .
2008/8/5 Peter Dimov
Not exactly, but the end result is the same. Python does pass a raw pointer (PyObject*) to the Boost.Python translation layer. Boost.Python then constructs a specially crafted shared_ptr<A> from that. There is no implicit conversion from T* to shared_ptr<T>. _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users