On Fri, Mar 21, 2008 at 10:52 PM, Steven Watanabe &lt;<a href="mailto:watanabesj@gmail.com">watanabesj@gmail.com</a>&gt; wrote:<br><div class="gmail_quote"><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
AMDG<br>
<div class="Ih2E3d"><br>
Robert Dailey wrote:<br>
&gt; Will the plain_return_type_2 specialization also work for classes<br>
&gt; derived from Stream? Or do I need to specialize that structure for<br>
&gt; each and every single class, regardless of inheritance? Thanks.<br>
<br>
</div>Yes, you would need to specialize for every derived class.<br>
The other alternative is to use an explicit return type.<br>
<a href="http://www.boost.org/doc/html/lambda/le_in_details.html#lambda.overriding_deduced_return_type" target="_blank">http://www.boost.org/doc/html/lambda/le_in_details.html#lambda.overriding_deduced_return_type</a></blockquote>
</div><br>How about Boost.Bind? Could I use it to bind my operator? I would also
expect it to choose the correct overload of the stream operator
depending on the type of _1. I have not used Bind like this before, so
I&#39;m not sure if it is capable. If all else fails you&#39;ve given me 2
alternatives concerning Boost.Lambda, so I could always go with that.<br>
<br>
Thanks for all the help.<br>