Re: [Boost-users] [enable_if] Why any other than lazy?

On Fri, Aug 8, 2008 at 10:22 PM, Steven Watanabe <watanabesj@gmail.com>wrote:

AMDG For example

template<class T> typename boost::enable_if<boost::is_arithmetic<T>, T>::type foo(const T&);

There is no point to using the lazy versions.

Understood, but how would that be rewritten using lazy versions? It is more complicated than simply replacing enabe_if with lazy_enable_if? - Rob. -- ACCU - Professionalism in programming - http://www.accu.org