On Tue, Jan 15, 2013 at 5:49 PM, Steve Lorimer
Think about what happens if you feed multiple elements via operator% and then call .str() - you get a std::string back - it has to store everything you've fed in internally so that you can access the formatted string later via .str()
Steve, Thank you. I never used boost::format::str, but I agree that its presence indicates that operator% must alter an internal state. Question 1: Is there an efficient way to do the following (and by "more efficient" I mean fewer format constructors and string parsing): void WriteLog(float x, float y, float z, const Employee& e) { std::cout << "Values: " << boost::format("%0.3") % x << e << boost::format("%0.3") % y << boost::format("%0.3") % z; } Question 2: Is there a more efficient way to do this: std::string FloatToString(float x, int DigitsAfterDecimal) { std::ostringstream FormatStream; FormatStream << "%0." << DigitsAfterDecimal; boost::format Formatter(FormatStream.str()); Formatter % x; return Formatter.str(); } Thank you, Chris