Re: [Boost-users] [boost-users][lambda] calling a functor in-place

Great, thanks a lot to both of you!

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As shown here: http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lamb..., the bind() is unavoidable, but it does not have to be that explicit. This should work: std::for_each(functors.begin(), functors.end(), bind(_1));

Cute! Hadn't realized the first argument of bind can also be filled by a placeholder.

Joaquín M López Muñoz Telefónica, Investigación y Desarrollo

With Boost.Bind, however, the same trick does not work:

std::for_each( functors.begin(), functors.end(), boost::bind(::_1));

This does not invoke operator() on the functor objects.