Re: [Boost-users] [function]unwanted conversion

Sean Huang wrote:

Is there any reason why boost::function allows such conversions?

Boost.Function tries to behave as if it were a function pointer. And like all pointers, function pointers can be assigned an integral constant with the value 0, resulting in a null pointer. Thus, you can assign 0 and char() to a Boost.Function. Sebastian Redl