Aljaz wrote:
Do I have to register_type this way? Can I use BOOST_EXPORT .. instead?
Yes
I tried doing BOOST_CLASS_EXPORT(B), but program crashed when I wanted to deserialize data..
I don't know what to say here. Its been tested, demo'ed and documented. .
Why I want to ID derived class through base class? Because derived class will contain a lot of data, that wont be in base class.
This topic is addressed in Scott Meyers "Effective C++"
I already made function get_type() that returns type of derived class.. But I still have no idea if I have smart pointer to base class, how do I get smart pointer do derived class from it?
I would expect one could do a dynamic cast of the shared ptr - but this is really a question for someone else.
Is there any example using extended_type_info family to do something similar?
I looked at the documentation for extended_type_info which requires the implementation of get_derived_type_info for each kind of extended_type_info object created. However its not document for general usage. I suppose that this is because that I didn't think it would be used for anything other than an implementation detail. Subsequently however, I used it as part of boost/serialization/detail/shared_ptr_helper. You can look into that file to see how this was done. Robert Ramey