Re: [Boost-users] [range] What's the best way to initialize a new container from a range?

29 Aug 2011

      On 26.08.2011 20:21, Ovanes Markarian wrote:
...
On Fri, Aug 26, 2011 at 2:30 PM, Martin B. <0xCDCDCDCD@gmx.at
mailto:0xCDCDCDCD@gmx.at> wrote:
Hi!
Say I have a range R and I want to construct a new container from
    the range R. Will I always have to repeat the expression yielding
    the range, or is there a shorter way?
Example:
std::vector<int> numbers(
          boost::irange(7, 42).begin(),
          boost::irange(7, 42).end()
        );
Note that it's just an example.
Is it possible to create a container C from a range expression R in
    one step? Any helper function for this?
What about that:
...
integer_range<int> ir=irange(7,42);
vector<int> numbers(ir.begin(), ir.end());
For this to work I need the exact type of the range, which can be quite 
annoying as far as I could tell. (Plus, I *don't want* to care what type 
of the range is.)

Really, if I had C++11/auto, I wouldn't mind so much, i.e.

     auto xr = get_some_range(...);
     vector<int> numbers(xr.begin(), xr.end());

but I don't have an `auto` capable compiler, so spelling out the range 
type for this is really crappy.

Writing a make_container function seems fiddly wrt. to the C++03 
reference type of the passed range, but maybe someone can help:

     template
     C make_container(R /*value? ref? const-ref?*/ range) {
       return C(range.begin(), range.end());
     }

and it would still be very ugly to call:

     const vector<int> numbers =
       make_container< vector<int> >(irange(7,42));

(Note: I did not compile/test this code!)

any ideas?

cheers,
Martin