Re: [Boost-users] [variant] how to get 1st bounded type

At least what I read here is following: All instances v of type variant guarantee that v has constructed content of !!!one!!! of the types !!!Ti!!!, even if an operation on v has previously failed. For me it means that it can be T2 or TN as well.

Right, but the 1st link says: "boost::variant< int, std::string > v; By default, a variant default-constructs its first bounded type, so v initially contains int(0). If this is not desired, or if the first bounded type is not default-constructible, a variant can be constructed directly from any value convertible to one of its bounded types. " _________________________________________________________________ Invite your mail contacts to join your friends list with Windows Live Spaces. It's easy! http://spaces.live.com/spacesapi.aspx?wx_action=create&wx_url=/friends.aspx&mkt=en-us