Re: [Boost-users] [lambda] std::sort problem

On Sun, Jan 25, 2009 at 9:46 AM, Michał Nowotka wrote:

Ok, but there is another problem.

Suppose i defined: typedef MyType std::pair;

So if I want to keep DRY i should write:

lambda::_1 ->*&MyType::value_type::second > lambda::_2 ->*&MyType::value_type::second);

I also tried: bind(&MyType::value_type::second, lambda::_1) > bind(&MyType::value_type::second, lambda::_2)

but none of this expression works for me.

Shouldn't that be &MyType::second - std::pair has no value_type? Stuart Dootson