Re: [Boost-users] [Q] using boost operators return types

At 09:55 AM 3/23/2009, V S P wrote:

I am using this example http://www.boost.org/doc/libs/1_38_0/libs/utility/operators.htm#example

but cannot understand why object is returned from those operators and not an object reference

That certainly is odd. It means that the following code will not work as expected: point x(0,0), y(1,0), z(0,1); (x += y) += z; // x is (1,0), not (1,1).

second, I do not quite understand, what exactly is a set of 'automatically generated' operators and would I figure that out.

It is documented in the comments of the example you cite, and listed in the table[1] just below. [1] http://www.boost.org/doc/libs/1_38_0/libs/utility/operators.htm#smpl_oprs