Re: [Boost-users] math tools roots

Viatcheslav.Sysoltsev@h-d-gmbh.de wrote:

On Sun, 09 Oct 2011 19:04:39 +0200, Matwey V. Kornilov wrote:

...

and, actually let a=b=x,

lim_{x->0} ((x-x)/min(|x|,|x|)) = lim_{x->0} (0/min(|x|,|x|)) = lim_{x->0} (0) = 0

I'am not active mathematician, but I believe lim {x->0} (0/x) is 0/0 and thus considered undefined, not 0.

lim 0/x is 0, but the original expression (with a and b) has no limit when a, b -> 0. If we let a = 2x, b = x, for example, we get lim(x->0) x/|x| which is either +1 or -1.