Re: [Boost-users] Getting the argument types from a function type

"Kirit Sælensminde" <kirit.saelensminde@gmail.com> wrote

I've been playing around with a few functional programming idioms in C++ using Boost.function and Boost.lambda and was wondering if it was possible to fetch out the argument type (i.e. int) from a type like this:

void (*somefunc)( int )

You don't need any libraries for this -- just use partial template specialization: template<class T> struct deduce_arg; //not defined template<class A> struct deduce_arg<void(*)(A0)> { typedef A0 type; }; Regards, Arkadiy