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Thanks for the info. Can it be done (at all, at the moment, elegantly,
practically, by turning a std::type_info into a type) ?
On 30 January 2010 19:58, Steven Watanabe
AMDG
Alan Tennant wrote:
Firstly. Thank you very much team Boost, it looks like it will be very useful and solve many of my coding problems.
I can create an any boost::any a1;
I can assign something to it a1 = string1;
I can get it back out later std::cout<
std::string(a1); A boost any has a "type()" method.
However this produced an error.
std::cout<
(a1); Template parameters have to be types. The result of a1.type() is a std::type_info object.
In Christ, Steven Watanabe
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