Re: [Boost-users] Template instantiation function arguments and Boost.Preprocessor

28 Jan 2008

      sorry, I have overseen it somehow... Probably too late already... That's
true, that array argument to a function is a pointer.  Sorry.

I have tested the code with gcc under MacOS X, the function with arguments
as 3 doubles was NOT necesserely faster as the boost::array param. It might
be not worse implementing the macro based approach...

Here is my test app compiled with O3 optimization flags. (Below are the
timing on a Dual Core 2.4 processor  machine with 4 gb ram)

//============================================================================
// Name        : CppTest.cpp
// Author      :
// Version     :
// Copyright   : Your copyright notice
// Description : Hello World in C++, Ansi-style
//============================================================================

#include <iostream>

#include <numeric>

#include 
#include 

using namespace std;

typedef boost::array array_type;

array_type::value_type sum_arr_copy(array_type a)
{
    return (a[0]+=a[1])+=a[2];
}

array_type::value_type sum_carr(array_type const& a)
{
    return a[0]+a[1]+a[2];
}

array_type::value_type sum_carr_temp_result(array_type const& a)
{
    double result=a[0];
    return (result+=a[1])+=a[2];
}

array_type::value_type sum_carr_accumulate(array_type const& a)
{
    return std::accumulate(a.begin(), a.end(), 0);
}

array_type::value_type sum_arr_copy_accumulate(array_type const& a)
{
    return std::accumulate(a.begin(), a.end(), 0);
}

double sum_doubles_copy(double d1, double d2, double d3)
{
    return d1+d2+d3;
}

double sum_doubles_copy_optimized(double d1, double d2, double d3)
{
    return (d1+=d2)+=d3;
}

double sum_doubles_copy_temp_result(double d1, double d2, double d3)
{
    double result=d1;
    return (result+=d2)+=d3;
}

double sum_doubles_ref_temp_result(double const& d1, double const& d2,
double const d3)
{
    double result=d1;
    return (result+=d2)+=d3;
}

/// sorry for macro code. I was too lazy to copy paste it...
#define ARR_P() a
#define DBL_P() d1,d2,d3

#define DO_TEST(function, param_seq)            \
{                                                \
    cout << "--------------------------\n"        \
         << #function"\n";                        \
    double result=0;                            \
    {                                            \
        boost::progress_timer t;                \
        for(unsigned long i=0; i wrote:
...
AMDG
Hicham Mouline wrote:
...
After some though, here is more precisely what I'd like to have...
I apologize that it is quite different from the initial problem:
template<int n> class Tree {
  static double sum();  //
};
If the user instantiates tree<2>, he should get:
template<> class Tree<2> {
  static double sum(double d1, double d2);
};
template<> class Tree<3> {
  static double sum(double d1, double d2, double d3);
};
etc etc...
so that in user code, for e.g.:
double d= Tree<4>::sum(d1, d2, d3, d4);
should compile.
Is it possible for me to just define the template Tree for the n-case
without the 2- and 3- specializations?
Ah.  You still need the preprocessor, but you can rearrange the
definitions slightly.
(untested)
template<int N>
struct TreeSumImpl;
#define TREE_SUM_DEF(z, n, data)\
   template<>\
   struct TreeSumImpl<n> {\
       static double sum(BOOST_PP_ENUM_PARAMS_Z(z, n, double arg)) { ...
}\
   };
BOOST_PP_REPEAT(20, TREE_SUM_DEF, ~)
template<int N>
struct Tree : TreeSumImpl<N> {
   // other code
};
In Christ,
Steven Watanabe
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Re: [Boost-users] Template instantiation function arguments and Boost.Preprocessor

Ovanes Markarian