Re: [Boost-users] Conditional function definition with boost::enable_if

2009/2/10 Matthias Vallentin :

On Tue, Feb 10, 2009 at 09:34:20PM +0100, Matthieu Brucher wrote:

...

Would it be possible to derive from a class that has this function? This way, the mother class is template, the template argument being the child class (the curiously recursive template pattern). Then, in the mother class, you can define f() and call i(). I don't know how i() would be exactly called, but you get the idea.

Could you substantiate your solution with a short example, I think I don't understand which direction you're heading. What I'm trying to accomplish and express in code is the following idea:

If you provide a function (i), you get functionality from the parent (f).

Matthias -- Matthias Vallentin vallentin@icsi.berkeley.edu http://matthias.vallentin.cc _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users

Something like (not the correct code though): template<class Child> struct MyfStruct { typename boost::enable_if::type f() { // Do some stuff, but I don't know how to call i(), you will have to test :| } }; where has_i<> tests if the child has the method i(). Then, if you find how to call i() from the f() method, you just have to write: class MyClass: public MyfStruct<MyClass> { void i(); // f() will be callable now }; Matthieu -- Information System Engineer, Ph.D. Website: http://matthieu-brucher.developpez.com/ Blogs: http://matt.eifelle.com and http://blog.developpez.com/?blog=92 LinkedIn: http://www.linkedin.com/in/matthieubrucher